# How would you find the probability of selecting 3 red marble and 2 green marble or 1 yellow marble and 2 orange marble out of a bag of 12 marbles [closed]

How would you find the probability of selecting 1 red marble and 1 green marble or 1 yellow marble and 1 orange marble out of a bag of 12 marbles

There are four red marbles,one green marble, one yellow marble, six orange marbles

## closed as off-topic by Leucippus, Daniel W. Farlow, NCh, José Carlos Santos, JonMark PerryJun 19 '17 at 7:01

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• how many of each type are in the bag?? – Saketh Malyala Jun 18 '17 at 22:09
• @SakethMalyala I added amount of each type in edit – Math Skillz Jun 18 '17 at 23:34
• Have you tried to solve this on your own? – Gerard L. Jun 18 '17 at 23:36
• Yep I have tried – Math Skillz Jun 18 '17 at 23:42
• Are we to assume that two marbles are selected without replacement? – N. F. Taussig Jun 18 '17 at 23:59

The probability of picking a red marble is $4/12$. The probability of picking a green marble is $1/11$, since I'm assuming that the marbles are not replaced. You multiply since you want both of these occuring. $1/3$ times $1/11$ equals $1/33$.