The ratio of sines of the angles in a triangle is $5:6:7$. Find the ratio of cosines of this triangle in its simplest form.
This question was asked in a recent trigonometry test, and many had no idea how to answer it. Our class has only covered basic trigonometry up to sums or differences as products.
How would someone approach and answer this question?
Some approaches I've brainstormed are:
1)Using sine=opposite/hypotenuse and cosine=adjacent/hypotenuse (I would have no clue how to continue this)
2)Find an equation involving the ratios and sine and use $\cos\theta= \sin(90 - \theta)$ (angles are in degree units)
3)Find an equation from the sine rule and substitute the cosine rule (?)
Sorry, I don't know how to format this properly!