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I am truly embarrassed to admit my lacking knowledge of the Set Theory. Something always boggled my mind:

Suppose that we have an empty set $\emptyset$. By extension, we can write it as $$\emptyset = \{\}$$ which denotes the fact, which clearly states that $\emptyset$ is NOT a mathematical "nothing", rather it is a set whose power is $0$ (please, correct me if I'm wrong). We write $$\mathrm{card}(\mathcal{A}) = 0 \Longleftrightarrow \mathcal{A} = \emptyset.$$ As previously stated, an empty set is a set, which contains "nothing", but is not "nothing" by itself. Here I bump into a nasty problem. I immediately saw an iterative extension, which is (because of my lacking knowledge) very disturbing: $$\emptyset = \{\} \neq \{\emptyset\} \neq \{\{\emptyset\}\} \neq \{\cdots \{ \emptyset \} \cdots\}.$$

Let me explain the notation: Suppose that we have a set $\mathcal{A}$ which includes an empty set $\emptyset$. By standard deduction we conclude that $\mathrm{card}(\mathcal{A}) = 1$. But if an empty set is something that includes "nothing" shouldn't be any number of iterations of empty sets be considered "empty" only at the last "iteration"? Therefore, we can have a custom $\mathrm{card}(\mathcal{A})$ which really consists only of "nesting" one empty set.

I kindly ask you, can you present me the physiology of an empty set so that all the ambiguities (I am of course guilty of them) will be cleansed? I apologise if my question is too broad, but I can't put it another way.

EDIT: It would be helpful if you defined a mathematical "nothing" (is there such an area of mathematics that deals with the idea of "nothing"; sorry if I'm getting too philosophical).

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  • $\begingroup$ Not an answer, but just wondering: By 'power', do you mean the size of the set? Are you confusing $P(A)$ with $|A|$? $\endgroup$ – Bram28 Jun 13 '17 at 16:59
  • $\begingroup$ Since the empty set has no elements in it, it does not possess any qualities that might give it a physiology. $\endgroup$ – Hans Engler Jun 13 '17 at 17:02
  • $\begingroup$ Yes, I am just about to edit my mistake. In my country, we use $P(\mathcal{A})$ as a $\mathrm{card}(\mathcal{A})$ rather than for a Power set. I didn't know about the $|\mathcal{A}|$ until now. $\endgroup$ – Gregor Perčič Jun 13 '17 at 17:03
  • $\begingroup$ I am quite confused as to what you are suggesting ... or asking ... but maybe this helps: We can think of an empty set as an empty bag. And the empty set containing the empty set would be a bag with another bag in it ... where the latter is empty.... and so on ... so these are all different 'physically' ... $\endgroup$ – Bram28 Jun 13 '17 at 17:04
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    $\begingroup$ @Bram28 The "power" of a set was indeed an old term for its cardinality. We can still see the traces of this terminology in the use of the word "equipotent" for "of the same size," literally meaning "having the same power." $\endgroup$ – Noah Schweber Jun 13 '17 at 17:08
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Let me see if I can explain how one proves that each of the sets in that chain is distinct from the next.

First, you're quite correct that $\emptyset\neq \{\emptyset\},$ by Extensionality, since $\emptyset\notin\emptyset.$

Now, let's say we've just shown that one of the sets in the iteration isn't equal to the next. That is, we've just shown that $A\neq B,$ where $B=\{A\}.$ The next set in the iteration will be $\{B\}.$ As we have just shown that $A\neq B,$ then by Extensionality, we have $\{A\}\neq\{B\},$ meaning $B\neq\{B\}.$ Iterating this argument takes us as far along the chain as we care to go.

In fact, we can go further and say that none of the sets in the chain are equal, but this takes quite a bit more work. However, Extensionality immediately shows that $\emptyset$ is distinct from all other sets in the chain, since the rest have (exactly) one element.

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  • $\begingroup$ Thank you so much! You actually understood my unintelligible rambling, now I'm starting to see the light. Since you provided me with such a brilliant insight, I have to shamelessly ask you to answer another question: what is a mathematical definition of "nothing"? $\endgroup$ – Gregor Perčič Jun 13 '17 at 18:05
  • $\begingroup$ Well, often, this is defined as the content of the empty set. However, that depends on how the empty set is defined, as we must avoid circular definitions. How has the empty set been defined for you? $\endgroup$ – Cameron Buie Jun 14 '17 at 0:17
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The set $\{\emptyset\}$ does not contain nothing; it contains the empty set $\emptyset$. As you correctly observe, "$\emptyset$ is NOT a mathematical "nothing,"" so $\{\emptyset\}$ has one element. Note that in particular this means $\emptyset\not=\{\emptyset\}$ (as again you correctly observe); among other things, this means $\{\emptyset, \{\emptyset\}\}\not=\{\emptyset\}$.

A common analogy here is to think of sets as boxes. $\emptyset$ is an empty box; $\{\emptyset\}$ is a box containing another box, and that other box is empty. Clearly these are different objects. I find this analogy misleading in general (for instance, a box containing two empty boxes is different from a box containing one empty box!), but in this case I think it can be illuminating.

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$P(A)$ is the power set of $A$ or the set of all subsets of $A.$

The empty set is a subset of every set. And every set is a subset of itself.

$P(\emptyset) = \{\emptyset\} \ne \emptyset.$

For any set $A$ the cardinality of the power set.

$|P(A)|=2^{|A|}$

and

$|P(\emptyset)|=1$

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An empty set is not nothing ... it is a set that contains nothing, which is different. Think of it as an empty bag .. which is a bag, not nothing.

So: $\emptyset\not = nothing$

And therefore: $\{ \emptyset \} \not = \{ nothing \} = \{ \} = \emptyset$

so $\{ \emptyset \} \not = \emptyset$

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  • $\begingroup$ I already explicitly expressed this observation in my original post with this sentence: "...which denotes the fact, which clearly states that $\emptyset$ is NOT a mathematical "nothing", rather it is a set whose power is $0$ (please, correct me if I'm wrong)." What I am asking of you is a mathematical definition of nothing. $\endgroup$ – Gregor Perčič Jun 13 '17 at 17:20
  • $\begingroup$ @GregorPerčič ... as opposed to what an empty set is, you mean ... OK, I think I'm seeing your question now ... $\endgroup$ – Bram28 Jun 13 '17 at 17:21
  • $\begingroup$ Yes, exactly (I bet you are a mathematician; could you please mathematically define "nothing"; I'm sorry if I'm being too intrusive, but my curiosity just overwhelms me sometimes). $\endgroup$ – Gregor Perčič Jun 13 '17 at 17:23
  • $\begingroup$ @GregorPerčič Hmmm, "what is nothing" sounds like just the kind of question philosophers may wonder about ... did you look at the Wikipedia page for 'Nothing'? I do like what they say there ... 'nothing is not something, but rather the absence of something'... but maybe we can define 'nothingness' in a positive way? $\endgroup$ – Bram28 Jun 13 '17 at 17:25
  • $\begingroup$ Well, it's a shame that none of the great minds have taken a look at this (philosophically-heavy) question from mathematics' perspective. Or maybe you could suggest me some papers that analyze similar problems? $\endgroup$ – Gregor Perčič Jun 13 '17 at 17:33

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