The title is just an example and I didn't know what to call it. If, for example, 100 of an item costs $1200 then how much would one of that item cost?


closed as off-topic by Vidyanshu Mishra, Lord Shark the Unknown, kingW3, Namaste, NCh Jun 10 '17 at 21:12

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    $\begingroup$ What's the discount for buying in bulk? $\endgroup$ – Lord Shark the Unknown Jun 10 '17 at 6:20
  • $\begingroup$ Why down vote? Is there any guideline that disallows such questions? $\endgroup$ – baharampuri Jun 10 '17 at 7:39
  • $\begingroup$ @baharampuri: I'm not the down voter, but a down vote does not mean the subject matter of a Question is "disallowed". If you hover a mouse over the voting arrows, you'll see a tool tip that gives the message "This question does not show any research effort; it is unclear or not useful". $\endgroup$ – hardmath Jun 10 '17 at 15:13
  • $\begingroup$ I am aware of it, but what amount of research one can expect for this question which obviously is coming from a beginner. Here clearly the OP is asking for the method which was not introduced to him/her which is why he/she says it's an example. $\endgroup$ – baharampuri Jun 10 '17 at 18:56

Method 1.

$$100x = 1200 \implies x = \frac{1200}{100} = 12$$

Thus, a unit costs $12\text{ \$}$.

Method 2.

Let $N_1 = 100$ be the number of units bought initially, and $P_1 = 1200$ be the price for the $N_1$ items.

Let $N_2 = 1$ be the number of units one wants to buy, and $P_2 =\:?$ be the price for $N_2$ units.

Now you should find the ratio between price and number of units: $$r=\frac{P_1}{N_1}$$ $$r=\frac{1200}{100} = 12$$

Now multiply by $N_2$ units to get the final price: $$P_2=N_2\cdot r$$ $$P_2=1 \cdot 12 = 12 \text{ \$ (dollars)}$$

Method 3. - The rule of three

$$100 \text{ units ............ 1200 \$}$$ $$1 \text{ unit ............ n \$}$$

$$n = \frac{1200 \cdot 1}{100}$$ $$n = 12$$

However, I think one should be offered a discount for buying $100$ units over just $1$ item...


Hint. Let $p$ be the price of one item. If 100 of them costs 1200 then the following equation hold $100\times p=1200$.

Are you able to find the value of $p$?


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