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Find the GCD and the LCM of 24,48 and 96 ,then compare the multiplication of those numbers and the multiplication of the GCD and the LCM.

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closed as off-topic by Henrik, lulu, kingW3, Davide Giraudo, zz20s Jun 9 '17 at 13:34

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Henrik, lulu, kingW3, Davide Giraudo, zz20s
If this question can be reworded to fit the rules in the help center, please edit the question.

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    $\begingroup$ Sounds straight forward, what have you tried? $\endgroup$ – lulu Jun 9 '17 at 11:38
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    $\begingroup$ Done. What should I do now? $\endgroup$ – Henrik Jun 9 '17 at 11:38
  • $\begingroup$ You should post it as your answer @Henrik . $\endgroup$ – Harsh Kumar Jun 9 '17 at 11:39
  • $\begingroup$ @Henrik If this question gets closed because of lack of context, the system will close it in 30 days (with its current 3 downvotes) and reverse any reputation gains from this question. $\endgroup$ – Toby Mak Jun 9 '17 at 11:50
  • $\begingroup$ Contest math? It would be an assignment for primary school students. $\endgroup$ – edm Jun 9 '17 at 11:51
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Although this is not a site for homework questions, maybe you are unfamiliar with the algorithm - Through prime factorization: $$24=2^3\cdot 3$$ $$48=2^4\cdot 3$$ $$96=2^5\cdot 3$$

$$\gcd(24,48,96) = \gcd(2^3\cdot 3,2^4\cdot 3,2^5\cdot 3) = 2^3\cdot 3 = 24$$ Following the same method: $$\text{lcm}(24,48,96) = 96$$ Then, it is obvious that: $$96 \cdot 24 < 96 \cdot 24 \cdot 48$$


There are other methods as well, such as Euclid's Algorithm.

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