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Find the total number of local maxima and local minima for the function $$ f(x) = \begin{cases} (2+x)^{3} &\text{if}\, -3 \lt x \le -1 \\ (x)^\frac{2}{3} &\text{if}\, -1 \lt x \lt 2 \end{cases} $$

My attempt : I differentiated the function for the two different intervals and obtained the following: $$ f'(x) = \begin{cases} 3\cdot(2+x)^{2} &\text{if}\, -3 \lt x \le -1 \\ \frac{2}{3}\cdot (x)^\frac{-1}{3} &\text{if}\, -1 \lt x \lt 2 \end{cases} $$ How do I obtain the maxima and minima points from here.

Any help will be appreciated.

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    $\begingroup$ extrema occur where $f'(x) = 0$, $f'(x)$ is undefined, and/or endpoints. $\endgroup$ – Dando18 Jun 6 '17 at 14:12
  • $\begingroup$ @Dando18, "extrema may occur where..." In the problem given, $f'(-2)=0$ but $(-2,0)$ is not an extrema. $\endgroup$ – Bernard Massé Jun 6 '17 at 14:28
  • $\begingroup$ @BernardMassé Yeah I meant $ \text{extrema} \implies f'(x)=0,\, \dots$ not the other way around. $\endgroup$ – Dando18 Jun 6 '17 at 14:30
  • $\begingroup$ Just draw the graph?! $\endgroup$ – Pieter21 Jun 6 '17 at 15:30
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You need to study $f'$ :

What is the sign of $f'(x), x\in ]-3 , 2 [$ ?

A local maxima/minima $x_m$ appears when :

  • $f'(x_m) = 0$ or $x_m$ is a remarquable point (here $x_m \in \{-3,-1,2\}$)
  • $f'$ changes sign before and after $x_m$

If the second condition is not verified, $x_m$ is an inflection point.

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  • $\begingroup$ I think x=0 is another remarkable point here, since f'(x) becomes undefined at x=0 . $\endgroup$ – MathsLearner Jun 6 '17 at 15:30
  • $\begingroup$ You're absolutely right, I didn't do the $f'$ study before posting my answer but indeed as pointed out by Dando18 if $f'$ is undefined then you should check the nature of the point. $\endgroup$ – Furrane Jun 8 '17 at 2:38

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