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I have to find the image of the disk |z| $<$ 1 under the Mobius Transformation w(z) = $\frac{iz-i}{z+1}$. This is how I approached it:

Since every Mobius function is determined uniquely by its action on three points. I took three points on the boundary of the disk (i.e. unit circle) i, 1 and -i whose images were -i, 0 and 1 respectively.

Since Mobius transformations are conformal and the unit disk was on the right hand side of the three points, the image must be on the right hand side of the three images. This implies that the image must be the 4th quadrant, excluding the positive real axis and negative imaginary axis.

Is this a valid solution? I was trying to attempt a lot of exercises like this during self-learning complex functions. Is my approach rigorous and valid enough?

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  • $\begingroup$ Mobius transformations map circles to lines or circles, so the image of the unit disk can be either a disk or a half-plane, but never a quadrant. $\endgroup$ – dxiv Jun 6 '17 at 3:45
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    $\begingroup$ Your mistake seems to be your calculation of $w(i)$. $\endgroup$ – Lubin Jun 6 '17 at 3:59

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