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$\frac{1}{4} (\frac{1}{4} \sec^2(\frac{1}{4}) + 2\tan(\frac{1}{4})) $

How do I input $\sec^2 $ onto the calculator ?

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closed as off-topic by Zain Patel, Lord Shark the Unknown, B. Mehta, Leucippus, C. Falcon Jun 4 '17 at 1:21

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question is not about mathematics, within the scope defined in the help center." – Zain Patel, Lord Shark the Unknown, B. Mehta, Leucippus, C. Falcon
If this question can be reworded to fit the rules in the help center, please edit the question.

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    $\begingroup$ $1/cos^2(1/4) $ $\endgroup$ – bloomers Jun 3 '17 at 15:07
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    $\begingroup$ $ (1 \div \cos( 1 \div 4 ) )^2$ $\endgroup$ – Dando18 Jun 3 '17 at 15:08
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$$\sec(x)=\frac{1}{\cos(x)}$$ and $$\sec(x)^2=\frac{1}{\cos(x)^2}$$ and in your case $$\left(\sec(1/4)\right)^2=\frac{1}{(\cos(1/4))^2}$$

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  • $\begingroup$ This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review $\endgroup$ – The Count Jun 3 '17 at 15:29
  • $\begingroup$ can you tell me why? i know this phrase $\endgroup$ – Dr. Sonnhard Graubner Jun 3 '17 at 15:30
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    $\begingroup$ @TheCount: That is often a relevant critique to level at Sonnhard's answers, but it's a mystery to me how you think it applies here. $\endgroup$ – Henning Makholm Jun 3 '17 at 15:34
  • $\begingroup$ @HenningMakholm It doesn't at all help the poster get the requested thing into the calculator, it merely restates the rules for the trig functions. If you disagree, that's ok. $\endgroup$ – The Count Jun 3 '17 at 15:36
  • $\begingroup$ @TheCount: Are you seeing the same question as I see? This answer tells the OP exactly how he gets a calculator with standard keys to compute a secant for him -- which is what was asked. $\endgroup$ – Henning Makholm Jun 3 '17 at 15:37

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