I'm curious whether a function can take itself as an argument or return itself. That is to say: Is there a function $f$ such that $f() = f$? Or perhaps less confusingly if you aren't used to functions which don't take arguments: Is there a function $f$ and an object $x$ such that $f(x) = f$? To make it even more clear: This would imply that $(f(x))(x) = f(x) = f$.
Please don't confuse this with something like $\text{id}(\text{id}(5))$. What's happening here is that the outer (call to the)* identity function takes the result of the inner (call to the)* identity function as an argument, not the identity function itself.
* I have no idea how mathematicians would say this. Too much computer science, too little math. ;-) Would be nice if you dropped this in, though, so that I can learn about mathematical terminology.
def f(): return f
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