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Find the point at which the line x = 3-t ,y = -3t, z = 1-2t intersects the plane x+y-2z = 2 .

How to solve this question?

Is it only replace the x, y and z ?

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plugging $$x=3-t,y=-3t,z=1-2t$$ in the equation of the given plane we get $$3-t-3t-2(1-2t)=2$$ now solve this equation for $t$ we will find no real $t$ thus your line doesn't intersect the plane the line is parallel to the plane

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  • $\begingroup$ so the answer is 0 ? $\endgroup$ – Mohd Azimuddin May 25 '17 at 7:17
  • $\begingroup$ I know it's 2 years later... Is there any algorithm to get the point for any plane and any line? (In case they aren't parallel) $\endgroup$ – Falk May 28 at 20:55

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