If I draw five cards from a deck of 51 cards, how many possible arrangements possible if i want 2 cards with the same value ie 2 jacks?
My method in solving this was to do the following: (52)(3)(50C3)
Because the first card doesn't matter and the next one matters and the rest of the three don't matter at all.
I have a very strong feeling that I was overcounting and my method was flawed
i was wondering if I was making any mistakes?