# Solving algebra word problem?

A man has a set of jacks. He has $j$ jacks, which is twice as many jacks as he has balls $b$ . How many balls does he have?

Correct answer $b=\frac{j}{2}$. I think it should be $b=2j$ because he has "twice as many jacks as he has balls".

• What does $j$ stand for? – vadim123 May 21 '17 at 22:32
• $j$ is the number of jacks. – Frpzzd May 21 '17 at 22:33
• He has twice as many jacks as he has balls, so $j = 2b$. – N. F. Taussig May 21 '17 at 22:34

## 2 Answers

If $b=2j$, that implies that he has more jacks than balls. However, from the problem, you know that he has more jacks than balls, so the answer should be $b=\frac{j}{2}$.

If he has $5$ balls, how many jacks does he have? $10$? Then $5 = \frac{10}{2}.$