How to determine the total number of homomorphisms from $V_4 \rightarrow C_2$? How to determine the total number of homomorphisms from $V_4 \rightarrow C_2$? Where $V_4$ is the Klein-$4$ group and $C_2$ is cyclic of order $2$. 
So far I have managed to create $7$ just from playing about with the elements.
These are: The trivial homomorphism. $3$ homomorphisms in which all elements of $V_4$ are mapped to the identity in $C_2$ except one non identity element which is mapped to the non identity in $C_2$. And finally the $3$ homomorphisms taking $2$ distinct non-identity elements from $V_4$ and mapping them to the non identity in $C_2$.
I have a few questions. 
1) If $\phi:G \rightarrow H$ is a homomorphism what can we say about the order of elements? (I.e. is it true that $o(g)|o(\phi(g))$ or the other way around maybe?)
2) Are my maps correct and are the the only homomorphisms from $V_4$ to $C_2$.
3) Is there a nicer way to argue this question other than just trying to guess all possible ones?
Thanks!
 A: The Klein four group $V_4$ is isomorphic to $\mathbb{Z}_2\oplus \mathbb{Z}_2.$ $C_2$ is $\mathbb{Z}_2$. Since the groups are abelian homomorphisms from $\mathbb{Z}_2\oplus \mathbb{Z}_2$ to $\mathbb{Z}_2$ are $\mathbb{Z}$-linear maps $\text{Hom}_{\mathbb{Z}}(\mathbb{Z}_2\oplus \mathbb{Z}_2, \mathbb{Z}_2)$. Since $\text{Hom}_{\mathbb{Z}}(\mathbb{Z}_2,\mathbb{Z}_2) = \mathbb{Z}_2$ we have 
\begin{eqnarray}
\text{Hom}_{\mathbb{Z}}(\mathbb{Z}_2\oplus \mathbb{Z}_2, \mathbb{Z}_2) 
 & \cong & \text{Hom}_{\mathbb{Z}}(\mathbb{Z}_2, \mathbb{Z}_2) \oplus \text{Hom}_{\mathbb{Z}}(\mathbb{Z}_2, \mathbb{Z}_2)\\
& = & \mathbb{Z}_2 \oplus \mathbb{Z}_2.
\end{eqnarray}
A: (group theory perspective)
By the number of ways $C_2$ is partitioned into the quotient subgroups
of (together with maybe lagrange theorem) of $C_2$ which are isomorphic to the subgroups of $V_4$. By the isomorphism theorem. So the number of subgroups of $V_4$.
The group isomorphism theorem says for every sub group of $V_4$ there is a homomorphism $V_4\to C_2$ and the subgroup of $V_4$ is isomorphic to the quotient group of $C_2$. Thus one can think of the homorohisms from $V_4\to C_2$ as essentially the subgroups and vice versa. Homomorphisms up to isomorphism that is.
A: If you have already done linear algebra, you may notice that $V_4$ is a $C_2$ vector space with dimension $2$. This allows you to write all the functions as matrices of dimension $2×1$, since being an homomorphism is the same as being linear (check it!). Indeed, the only choices you can take is where to send the generators. 
Moreover, always given linear algebra topics, you're evaluating the cardinality of the dual space, that is isomorphic to $V_4$.
