Ok. So I have a question that gives me the equation of two circles stating that point $A$ and $B$ are the centre of these circles.
POINT $A$ is centre of circle: $(x-3)^2 + (y-11)^2 = 144$
POINT $B$ is centre of circle: $(x-12)^2 + (y+1)^2 = 9$
Part i) of the question asks to determine the length of $AB$, which I worked out using the distance formula to achieve $d= 15$ units.
Part ii) says "determine wether the circles have two points in common, just one point, or no points in common, and justify your answer."
This is where I'm lost and have no idea to work it out. I assume it may be something to do with $x$ and $y$ being equal in the two equations but then I don't know how to prove this.
Any help would be really appreciated. Thank you. Also, how do you know if $1$, $2$ or $0$ points intersect?