1
$\begingroup$

I will soon be taking an examination that will require me to solve $2$ simultaneous equations of the form $ax+by=0$ and $cx+dy=k$. I have access to a calculator but it does not solve these types of problems for me unfortunately.

The numbers are not nice to work with either like $a=0.479374, b=3.485493$ etc. And there will be a lot of time restrictions and pressure.

I wonder what is the best way to solve such a system of equations?

$\endgroup$
3
  • $\begingroup$ Try using the substitution/elimination method. $\endgroup$
    – Joe
    May 5, 2017 at 21:28
  • $\begingroup$ {en.wikipedia.org/wiki/…} $\endgroup$
    – avs
    May 5, 2017 at 21:41
  • $\begingroup$ Solve symbolically and substitute the values in the end only. $\endgroup$ May 6, 2017 at 1:03

2 Answers 2

3
$\begingroup$

Solve for $x$ and/or $y$ in terms of $a,b,c,d,k$.

$$x = \frac{k}{c - \frac{db}{a}} = \frac{ka}{ca-db}$$

$$y = -\frac{b}{a}x$$

In this case, plug in $a,b,c,d,k$ to find the solution for $x$, and then use that value for $x$ to find $y$.

$\endgroup$
0
$\begingroup$

Plug and chug

$$ \begin{align} g & = a d - b c \\ x & =-b \frac{k}{g} \\ y & = a\frac{k}{g} \end{align} $$

$\endgroup$
1
  • $\begingroup$ Obviously you keep $\frac{k}{g}$ in memory because it is used twice. $\endgroup$ May 6, 2017 at 1:08

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .