I wanna know how to find angles of trapezoid (approx) with Bases and legs. Bases are 10cm and 13cm and legs are 6cm and 4cm. Thanks!!
Label the vertices of the trapezoid $ABCD$ in sequence around the trapezoid so that its bases are $AB=10$ and $CD=13$ and its legs are $AD=6$ and $BC=4.$
Put $P$ on the line between $C$ and $D$ such that $CP = 10.$ Then the quadrilateral $ABCP$ is a parallelogram, and $AP = BC = 4.$
This problem should be much easier to solve than the original one appeared to be.