To solve ${x^2} - 15x + 56 = 0$ use the formula $\ x = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$ where b = - 15,a = 1,c = 56. Is there a mathematical symbol I can use for "where" in this?
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$\begingroup$ No! Maybe comma $","$ is the best symbolic way to write it out instead. $\endgroup$– user321268Apr 26, 2017 at 16:38
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$\begingroup$ Personally I think it reads better with 'where' left in rather than trying to compress the notation any more. $\endgroup$– DMcMorApr 26, 2017 at 16:39
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$\begingroup$ (let a in f a) and (f a where a is ...) are already mathematical constructs; there's no need for a symbol. They are equivalent to (\a. f a)(b) $\endgroup$– DmytroApr 26, 2017 at 17:52
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$\begingroup$ I like the "where", but my Latex editor doesn't like me putting words and spaces into equations and it breaks the flow if I have to switch to plain text. $\endgroup$– Michael McLaughlinApr 27, 2017 at 12:35
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$\begingroup$ surely there's a workaround for making it usable; latex tends to be very clunky without the right modules $\endgroup$– DmytroMay 1, 2017 at 11:42
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1 Answer
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$$ x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\bigg|_{b=-15, a=1, c=56} $$
answered Apr 26, 2017 at 16:40
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