From a group of 10 men and 5 women, 4 member committees are to be formed each of which must contain at least one woman. Then the probability for these committees to have more women than men is:
Since each committee must have at least one woman, 4 women have already been placed into separate committees. There is one woman yet to be placed. For a committee to have more women than men, there can be 2 women and 0 men or 1 man. For a committee having only one woman, there must not be any more men in the committee.
This is what I could reason so far. But I don't know how to proceed.
Edit: I might have misinterpreted four-member committees (having 4 members) as 4 committees.