How would I express that a variable is a very small number? I was wondering if there were a mathematical way to note that a variable in an expression is "very small". I feel like ambiguity might be the cause of there not being one, but I'm not sure.
Example:
$\Delta A = \frac12 (r + \Delta r)^2 \Delta \theta - \frac12 r^2 \theta  = r (\Delta r \Delta \theta) + \frac12(\Delta r)^2 \Delta \theta \approx r \Delta r \Delta \theta$
Error in $\Delta A $ is the term $\frac12 (\Delta r)^2 \Delta \theta$ when $\Delta r$ and $\Delta  \theta$ are very small.
Is there a better way to write the bolded statement?
And on that note, is there a better way to write "Error in $\Delta A$"?
 A: Consider using Little o notation. This makes explicit what we mean by "a negligible error". We are ultimately interested in what happens as $\Delta r\to0$. If $f(\Delta r)=o(\Delta r)$ (i.e. if $\frac{f(\Delta r)}{\Delta r}\to0$ as $\Delta r\to0$), then $f(\Delta r)$ must be much smaller than $\Delta r$. Your final expression is a multiple of $\Delta r$, and so it is reasonable to group all lower order terms in one $o(\Delta r)$.
Another example: we know $\lim_{\Delta x\to0}\frac{\sin(x+\Delta x)-\sin(x)}{\Delta x}=\cos(x)$. We could rewrite this as
$$\sin(x+\Delta x)=\sin(x)+\Delta x\cos(x)+o(\Delta x).$$
The difference between $\sin(x+\Delta x)$ and $\sin(x)+\Delta x\cos(x)$ is not zero, but on the scale of $\Delta x$ it is so small that does not affect our limit.
A: You can write $\Delta r, \Delta\theta < \epsilon$, if that is what you are asking.
For the error part you could say, for example:
$$ e = \lVert\Delta A - \Delta A^*\rVert  $$
where $e$ is the error and $\Delta A^*$ the real value of $\Delta A$.
