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I don't remember how to resolve in the classical way an equation like

$$x^{4/5}>3x^{1/2}$$ I think to do: $$x^{4/5}>3x^{1/2} \iff \frac{x^{4/5}}{x^{1/2}}>3 \iff x^{3/10}>3 $$ (obviously for $x^{1/2}\neq 0$) but I'm not sure is the correct way...

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  • $\begingroup$ The $\iff$ only applies if both sides of the inequality are positive $\endgroup$
    – mrnovice
    Apr 7, 2017 at 16:34

1 Answer 1

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If u multiply or divide the unknown in an inequality it might change depending on x, for a proper way x^4/5 - 3x½ >0 , then take common x½ and you get two inequalities and take the intersection of both the answers, if you do so u will see you might have missed a set of answer.

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