0
$\begingroup$

Find the general equation of the circle containing $(-4,-2)$ and $(2,0)$, and whose center is contained on the line $5x-2y=19$.

$\endgroup$
1
$\begingroup$

Hint:

The center of the circle is the common point of the perpendicular bisector line of the segment that has as extremes the two given points, $A=(-4,-2)$ and $B=(2,0)$, and the given straight line : $5x-2y=19$.

$\endgroup$
3
  • $\begingroup$ How should I start solving this problem? $\endgroup$
    – KelDScnd
    Apr 5 '17 at 20:29
  • $\begingroup$ Do you know how to find the perpendicular bisector of a segment? If not you can see here: math.stackexchange.com/questions/545293/… $\endgroup$ Apr 5 '17 at 20:36
  • $\begingroup$ (y-y)=m(x-x) is that it? Uhm point-slope intercept form, is the name correct, I can only barely remember it $\endgroup$
    – KelDScnd
    Apr 5 '17 at 20:39

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.