Find the general equation of the circle containing $(-4,-2)$ and $(2,0)$, and whose center is contained on the line $5x-2y=19$.



The center of the circle is the common point of the perpendicular bisector line of the segment that has as extremes the two given points, $A=(-4,-2)$ and $B=(2,0)$, and the given straight line : $5x-2y=19$.

  • $\begingroup$ How should I start solving this problem? $\endgroup$
    – KelDScnd
    Apr 5 '17 at 20:29
  • $\begingroup$ Do you know how to find the perpendicular bisector of a segment? If not you can see here: math.stackexchange.com/questions/545293/… $\endgroup$ Apr 5 '17 at 20:36
  • $\begingroup$ (y-y)=m(x-x) is that it? Uhm point-slope intercept form, is the name correct, I can only barely remember it $\endgroup$
    – KelDScnd
    Apr 5 '17 at 20:39

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