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I am not sure how to set up the equation for this question or what steps i should be taking. Please help!

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  • $\begingroup$ The answer is B $\endgroup$ – Noah I Apr 3 '17 at 17:59
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[rate in]$=24 g/min$ [rate out]$=4(S/68)$ (four galons per minute leaked from the tank that has an amount of salt of $S/68$ As said in the wording of the problem,

$S'=$[rate in]-[rate out], $S'=24-S/17$. The solution is B as Noah said.

The solution is $S(t)=408-408e^{-t/17}$

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