I need to find a vector that is perpendicular to the line $3x-4y=6$.
I started with calculating slope of the line which I get $3/4$. A perpendicular line/vector would have a negative reciprocal slope if $-4/3$.
I also know that a perpendicular vector has an equation of ac+bd=0 but I wasn't sure if I needed the equation as well.
My thought was to find two points on the line $(2,0)$ and $(10,6)$ which form a vector but I didn't know where to go from there.