I was doing a question on rectangle and thought about the diagonals of it .
And just remembered about parallelogram and tried to prove or disprove that both the diagonals of parallelogram are greater than its sides but wasn't able to do so...
I have proved it for one diagonal but the second one is difficult for me to do
I let that parallelogram has one acute angle and one obtuse angle and diagonal opposing to obtuse angle makes a triangle in which it has to be greatest because it is opposite to greatest angle
For diagonal opposing acute angle, I tried cosine rule but it didn't help.
Please help to prove or disprove that both of diagonals of parallelogram are greater than its sides......!!!!