Outline for Method of Moments Estimation (MME).
Let $X_i \stackrel{iid}{\sim}\mathsf{Exp}(rate = \theta).$
Then $E(X_i) = 1/\theta,$ so $E(\bar X) = 1/\theta.$
Setting sample mean equal to population mean, gives
the MME of $\theta$ to be $\tilde \theta = \frac{1}{\bar X}.$
I have no idea what the 'revised MME' means.
Outline for Maximum Likelihood Estimation (MLE).
The likelihood function is
$$L(\theta) = \prod_{i=1}^n f_X(x_i|\theta) = \theta^n e^{-\theta T},$$
where $T = \sum_{i=1}^n X_i.$
Taking logarithms we get $\ell(\theta) = n\log(\theta) - \theta T.$
And setting the derivative $\ell^\prime(\theta) = 0$ gives
$\hat \theta = \frac{n}{T}= \frac{1}{\bar X}.$
Note: This is just to get you started. Please compare the above with the
notation and explanations in your textbook. There are some gaps to fill and some explanations to provide before this exercise is done. By the way,
$E(1/\bar X) \ne \theta,$ so neither the MME nor the MLE is unbiased.
(Sometimes MME's are unbiased, but not when the algebra to solve for them
involves nonlinear operations like taking the reciprocal.)
You might want to see the Wikipedia pages on MME
and on exponential distributions.