# What the result of multipling the eigenvalues by the eigenvectors? [closed]

Multiplying the eigenvalues by the eigenvectors. Does this give any meaningful result?

## closed as off-topic by Leucippus, Henrik, pjs36, Juniven, ShaileshMar 24 '17 at 23:58

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Suppose that $T$ is a linear transformation on some vector space and $\mathbf{v}$ is a vector in that space. Then $\mathbf{v}$ is an eigenvector of $T$ if and only if $\mathbf{v}$ is not the zero vector, and there is some scalar $\lambda$ such that
$$T(\mathbf{v}) = \lambda \mathbf{v}.$$
If $\mathbf{v}$ is an eigenvector, then $\lambda$ is its eigenvalue.
So if you have an eigenvector $\mathbf{v}$ with an eigenvalue $\lambda$, the significance of the product $\lambda \mathbf{v}$ is that it's the same as $T(\mathbf{v})$.