A 10 litre container holds a mixture of water and sugar, the volume of sugar being 15% of total volume. A few litres of the mixture is released and an equal amount of water is added. Then the same amount of the mixture as before is released and replaced with water for a second time. As a result, the sugar content becomes 10% of the total volume. What is the approximate quantity of mixture released each time?
I have tried:
Let the total litres be 10.
In that, let 15 percent be sugar so sugar contains 1.5 litres of the total volume of the mixture.
Then I calculated the ratio to be 1.5:8.5. For ratio calculating, I have taken the value as whole numbers, that is, 15:85.
Ratio is 3:17.
Let some amount of mixture released be x
3x/20 *1.5 + 17x/20*8.5
Then an equal amount of water is added in the mixture
3x/20*1.5 + 17x/20*8.5 + x
Second time same process is repeated means 10% of the total volume
(3x/20)^2*1.5 + (17x/20)*8.5 +2x
(3x/20)^2*1.5/(17x/20)*8.5 +2x = 1/9
I am doing this question correctly? If not, where is my mistake?
Please, anyone, guide me to the answer.
1.)1 litre 2.) 1.5 litre 3.) 1.2 litres 4.) 2 litres