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Is it just identity matrix product with identity matrix?

If I write $I = I \times I$, can it be proper form for LU decomposition $I = L \times U$?

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    $\begingroup$ Correct, see: wolframalpha.com/input/…, of course this extends to any $n \times n$ case. $\endgroup$
    – Moo
    Commented Mar 17, 2017 at 18:22
  • $\begingroup$ WHat is the problem with $L=I$ and $U=I$? $\endgroup$ Commented Mar 17, 2017 at 18:43

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