How to create a Dutch Book? I found this question from Ian Hacking's book on induction and probability. I understand that a Dutch Book is a gambling term wherein everyone wins. Although, the last part of the question 'Describe a Dutch Book for Dave' is confusing. How is this prediction one where everyone wins?

Dave thinks that the probability of an early Spring if Wiarton Willie
  predicts an Early Spring is 4/5, but that the probability of not
  having an early Spring if Wiarton Willie predicts an Early Spring is
  2/5. Describe a Dutch Book for Dave.

 A: Dave has managed to create a scenario in which he thinks if WW predicts an Early Spring, something will happen with a probability of $\frac65\gt1$.
This scenario is called a Dutch book - everybody knows that the maximum sum of probabilities can only be $1$, but the odds offered don't match with this, and hence there is a guaranteed profit for someone.
Let's assume WW predicts an Early Spring, Dave has two decisions, to go with WW or to reject WW's guess.
So Dave places £100 on both events at the odds he thinks he will get, but his mistake is in the way he calculated the odds. Elementary analysis reveals Dave's mistake:
A percentage $p\%$ to win equals $\frac1{1+w}$ where $w$ are the odds offered.
So $0.8=\frac1{1+w}\to1+w=\frac54\to 4w=1\to w=0.25$ and this gives odds of $4$ to $1$ on (stake £1, return £1.25).
And, $0.4=\frac1{1+w}\to1+w=\frac52\to 2w=3\to w=1.5$ and this gives odds of $3$ to $2$ against (stake £1, return £2.50).
An obvious scenario would be $P(\text{no Early Spring|WW says ES})=0.2$:
And, $0.2=\frac1{1+w}\to1+w=5\to w=4$ and this gives odds of $4$ to $1$ against (stake £1, return £5.00).
So Dave's on a loser because if he had correctly evaluated the probabilities, he could have got much better odds.
