# Prove that a function is growing over an interval

Suppose you have the function:

$f(x)=\frac{\frac{24x^3+24x}{(1+x^2)^4}}{4!}x^4$

And you want to find the value of the function in an interval $x \in [-1/2, 1/2]$.

Now, I know that the value in the outerpoints are as following:

$f(\frac{1}{2})=\frac{10}{81}$

$f(-\frac{1}{2})=-\frac{10}{81}$

My question is now:

How can I prove that this function is growing over that specific interval?

• Simplify your expression of $f(x)$. Find its derivative, simplify it and you'll see that $f'(x)>=0$ in the interval under consideration. Hence, $f$ is "growing over that specific interval" – Bernard Massé Mar 6 '17 at 20:53
• $f(\pm 1/2) = \pm 2/125$ if I'm not mistaken. Did you write it down wrong? – eyeballfrog Mar 6 '17 at 22:34

which is nonnegative over $[-\frac12,\frac12]$.