I am trying to solve the following question;
There are 3 news papers in a town, A, B, and C. 20% of the population read A, 16% read B, and 14% read C.
8% read A and B
5% read A and C
4% read B and C
2% read all
Determine the probability that a person reads none of the news papers.
I've realised I need to calculate what percentage of the population reads news papers.
To do this I've done the following;
A = 20 - 8 - 5 = 7
B = 16 - 8 - 4 = 4
C = 14 - 5 - 4 = 5
Population that reads News papers = 7 + 4 + 5 = 16
Therefore, 84 / 100 = probability a person doesn't read any news papers.
However, my answer is wrong. What is the best way to approach this problem?