# Height of vertical ropes of Golden gate bridge

The prompt is to find the parabola equation for the main span of Golden Gate bridge. Based on the $3$ points on the parabola: $(0,227)$; vertex $(640,75)$; and $(1280,227)$ I found the equation:

$$y = 0.00037109375x^2-0.475x+227$$

It is required to calculate the heights of vertical ropes under the parabolic main cable, which spans across a length of $1280$ m. Vertical ropes are distanced $15.24$ m apart with a diameter of $0.09736667$ m. The $x$-range is $[0,1280]$.

If I assume that the heights of vertical ropes follow the geometrical progression I get that $u = 219.8471693*0.968^{n-1}$. Where $u=$ height of vertical rope, $n=$ the number of the vertical rope in sequence.

I need a way to to prove if this equation is correct or not.

I tried by writing that \begin{align}219.8471693\cdot 0.968^{n-1} = & 0.00037109375\cdot(15.24n+0.09736667\cdot (n-1))^2 \\ & -0.475 \cdot (15.24n+0.09736667\cdot(n-1))+227\end{align} where L.H.S. is the function of height of vertical rope calculated by geometrical induction and R.H.S. is the height of vertical ropes calculated by using parabola function. $x$ at this point is the position of vertical rope on $x$-axis which is calculated by using the distance between ropes and diameter of one rope, and $n$ is the number of rope in the sequence. I tried to prove this equality by mathematical induction, but I couldn't.

How could it be proven that the heights of vertical ropes follow or not the geometrical progression?

• You may substitute 3 sets of numbers found from the quadratic equation at the top, the height of vertical ropes and calculate the common ratio. – GNUSupporter 8964民主女神 地下教會 Feb 24 '17 at 21:35
• Do you know that considering the curve is a parabola is only a raw approximation ? The true curve has equation $y=a \cosh(bx)$. – Jean Marie Feb 24 '17 at 21:46
• Common ratio to was 0.968 on 3 points, I assume it is a GP. – Archetype2142 Feb 24 '17 at 21:54

Ignoring (x,y) shift

$$y= k x^2, \quad k= y/x^2$$

$$k = (227. - 75)/640^2 = 0.000371094$$

Considering $(x,y)$ shift $= (h,k)$

$$(y - k) = k (x - h)^2$$

$$(y - 75) = k (x - 640)^2$$

The above is a parabolic progression. Please check your calculation. If a table of values (x,y) is given a parabola can be verified by numerically taking first differences twice ( like differentiating twice) from a table of (x,y) values.

Geometric progression is for an exponential curve!

We have a deep catenary suspension bridge cable of shape $y =c \cosh (x/c)$ if rate of loading $dQ/ds =$ constant with respect to sloping arc/arch/cable direction and is of shallow parabolic cable shape $y= c x^2$ if $dQ/dx =$ constant for constant loading with respect to span , the x direction. For the Golden Gate bridge the deck is horizontal and bears a constant load per meter, the error is not so high for its shallow arch and the latter is more accurately described as a parabolic bridge.