If $a+b+c=0$ and $\displaystyle \frac{1}{a}+\frac{1}{b}+\frac{1}{c} = 3$. where $a,b,c$ are non zero real numbers
then $ab(a+b)+bc(b+c)+ca(c+a)$ is
Attempt: from $a+b+c=0$ we have to find value of $-3abc$
and from $\displaystyle \frac{1}{a}+\frac{1}{b}+\frac{1}{c} = 3$ we have $\displaystyle \frac{ab+bc+ca}{abc} = 3$
could some help how to get value of $abc,$ thanks