Strange limit : $e=1$ Why the following is not correct? : $$\lim_{n \to \infty} (1+\frac1n)^n = \lim_{n \to \infty} (1+\frac1n) \lim_{n \to \infty} (1+\frac1n) \dots \lim_{n \to \infty} (1+\frac1n) = 1 \times 1 \times \dots 1 = 1.$$ I guess that the problem (as usual) lies in infinity, but if so how? I checked all the theorems in Fitzpatrick's book of Calculus, nothing prevents to do the limits infinitely many times (esp. for a convergent one)!
 A: Well one major problem is that you are, in a sense, taking the limit before taking the limit. How many terms are you multiplying?
A: You have written: 
$$\lim_{n \to \infty} (1+\frac1n)^n = \lim_{n \to \infty} (1+\frac1n) \lim_{n \to \infty} (1+\frac1n) \dots \lim_{n \to \infty} (1+\frac1n) = 1 \times 1 \times \dots 1 = 1,$$
But this is not correct, because it suggests a finite and unchanging number of quantities being multiplied together. As $n$ gets bigger, you multiply more. When $n$ is 20, for example, you have $(1+0.05)^{20}\approx2.65$, already. As you take away from the added term, you multiply more. And for no value of $n$ do you have that $\left(1+\frac{1}{n}\right)=1$.
Does this help?
A: In your first equality it seems that you equating two very different expressions: 
$$ \lim_{n\to\infty}\left[ \left( 1+\frac{1}{n}\right)^n\right] \text{and }\left[\lim_{n\to\infty} \left( 1+\frac{1}{n}\right)\right]^n$$
which are not equal. For a general expression $p(n)$,
$$\lim_{n\to\infty} \left[p(n)^n\right] \ne \left[\lim_{n\to\infty}p(n)\right]^n.$$
While this may be true for some $p(n)$, it must be shown to be true first before equality is taken. 
