Knowing the centroid of a triangle and the length of the sides can i find the coordinates of vertices? There seems to be a similar question in this exchange:
How could I use the centroid and size of a triangle to find the coordinates of its vertices?
But this one specifies that it has the centroid and the size of the triangle.
In my case what i am trying to do is to calculate the minimum bounding box for a triangle but i only have the following information:


*

*X, Y coordinates of the center of the triangle

*Length of the each sides.


Can anyone give me a hint? or this is also not possible.
Thx!
 A: The triangle is only determined up to rotations and reflections.
Let $G$ be the centroid of $\triangle ABC$. The length of the medians can be calculated in terms of the sides using the median length formula. That gives the length of $GA$ as $2/3$ the length of the median through $A$. Choose $A$ to be any point on the circle centered at $G$ of radius $GA$. Now construct $B$ knowing the distances $AB,GB\,$, then $C$ the same way. Depending on the choice of $B$ on either side of $GA$ this gives two possible triangles $ABC$ which are reflections of each other.
A: Another approach to prove reflection / rotation point. Sides of the triangle fully determine it in terms of congruence, i.e. for any two such triangles you can get one out of another with translation, rotation and reflection.
However any translation will move the center with the vector of translation, while rotation around its center will keep it.
We need also reflection, so basically we can split all possible solutions into two classes. Each one will have its own orientation and be 360 degree rotation of triangle defined by its sides around the center.
Another thing: the "center" can be not only intersection of medians, but any other uniquely defined point in or out of the triangle. 
