Prove or disprove that if $A$ and $B$ are dense, then $A \cdot B$ is dense There's this test question I'm having difficulty with. Let $A\subseteq \mathbb{R}$ and $B\subseteq \mathbb{R}$ be two sets in $\mathbb{R}$. Prove or disprove that if $A$ and $B$ are dense, then $A \cdot B$ is dense.
Note: If $A$ is dense then $\forall a_1, a_2 \in A, $ such that $ a_1 < a_2$ there exists $a_3 \in A$ such that $a_1 < a_3 < a_2$.
Also, we define $A\cdot B$ = $\{a \cdot b \mid a\in A$ and $b \in B\}$.
 A: Initial hint: Given $a_1 b_1$ and $a_2 b_2$ in $A*B$, you need to find $a_3 b_3$ with $a_1 b_1 < a_3 b_3 < a_2 b_2$. How do you think you should pick $a_3$ and $b_3$? 
Hint 2: Once you think this works, there's probably more to do. 
Post-comment addition:
OP writes:

Well I've tried to define $a_3=\frac{a_1+a}{2}$ and $b_3= \frac{b_1+b_2}{2}$ so $a_1 b_1<a_3 b_3<a_2b_2$ but this isn't true for $a_1=−1,a_2=0,b_1=1,b_2=5$, for example. How can I find those $a_3$ and $b_3$such that $a_1b_1<a_3b_3<a_2b_2$?

Doing that gives you a number $a_3$ that is between $a_1$ and $a_2$, but how do you know that $a_3 \in A$? (Answer: you don't, for its entirely possible that it's not.) You need some other way to produce $a_3$ and $b_3$. 
But as you note, that doesn't quite work -- negative numbers give you a problem. And now you have to think about whether the statement is actually true in cases where $A$ and $B$ have some negative numbers in them, or whether maybe it's false in those cases. 
By the way: nothing you described actually used the given fact that $A$ and $B$ are dense, and that's a bad sign, because the claim that $A*B$ is dense is certainly not in general true if $A$ and $B$ are not dense. 
Also: You might want to address the question raised in the comments in the original posting --- what definition of "dense" are you using? If it's "Dense in $\Bbb R$," then the claim is much easier to prove. 
A: Here is another point of view :
Given $A\subset\mathbb{R}$, we have :
$A$ is dense iff for all $x\in\mathbb{R}$, there exists a sequence of elements of $A$ which converges to $x$.
Now suppose $A,B$ are dense subsets of $\mathbb{R}$ and take $x\in\mathbb{R}$. There exist $(a_n)\in A^\mathbb{N}$ and $(b_n)\in B^\mathbb{N}$ such that $\lim_{n\to\infty}a_n=x$ and $\lim_{n\to\infty}b_n=1$; hence $\lim_{n\to\infty}a_nb_n=x$, which proves that $AB$ is also a dense subset of $\mathbb{R}$.
