Find the remainder of $\frac{3^{11}-1}{2}$ divided by $9$ I have the following question:

Find the remainder of $$\frac{3^{11}-1}{2}$$ divided by $9$

I tried to reformat the question:
$$\frac{3^{11} -1 } {2} \times \frac{1}{9} = \frac{3^{11}-1}{18}$$
Since $3^2 = 9$
$$\frac{3^2(3^9) -1}{3^2 \times2}$$
I don't know where to go next. Anyway, this is one of my many attempts to solve this question, and most of them ends with a complicated solution. I don't want to use modular arithmetic for this question. A hint or anything will help me. 
 A: We have that $$\frac {3^{11}-1}{2} = \frac {3-1}{2}(3^{10} + 3^9 + \cdots + 3^2+3+1) \tag {1} $$
We know that $3^2 =9 \equiv 0 \mod 9$ and similarly $3^3 =3 (3^2) \equiv 0 \mod 9$ and so on. Thus, $(1)$ reduces to, $$1 (0 + 0 + 0 \cdots 0 + 3 +1 ) \equiv 4 \mod 9$$
Hope it helps. 
A: $\frac {3^{11} - 1}{2} = \frac {3^{11} - 1}{3-1}=$
$3^{10} + 3^9 + .... + 3^2 + 3 + 1=$
$9(3^8 + ..... + 1) + 4$ 
so the remainder is $4$.
..or...
$\frac {3^{11}-1}2 = 3^{11}*\frac 12 - \frac 12 \equiv k \mod 9$
$ 3^{11}-1 \equiv 2k \mod 9$
$2k + 1 \equiv 0 \equiv 9 \mod 9$
$2k \equiv 8 \mod 9$
$k \equiv 4 \mod 9$.
A: The tool you need is modular arithmetic.
$3^{11}$ is congruent to $0$ mod $9$
$3^{11} - 1$ is congruent to $8$ mod $9$
The only hard part is the division. But, fortunately, you can uniquely divide by $2$ mod $9$:
$0*2 = 0,
1*2 = 2,
2*2 = 4,
3*2 = 6,
4*2 = 8,
5*2 = 1,
6*2 = 3,
7*2 = 5,$ and
$8*2 = 7$
so $8/2 = 4$ modulo $9$, thus the remainder is $4$.
A: $3^{11}$ is divisible by $9$.
So, $3^{11}  - 1$, when divided by $9$, will give a remainder of $8$.
Division equation- 
$a=bq+r$
$a= 3^{11}  - 1$
$b= 9$
$r= 8$
$3^{11}  - 1 = 9q + 8$
The $q$ given here will be even since $3^{11} - 1$ is even, $r$ is even and so $9q$ must also be even. Hence, $q$ is of the form $2k$ for some natural number $k$.
$3^{11}  - 1 = 18k + 8$
Divide both sides by $2.$ 
$3^{11}  - 1 = 18k + 8$
$(3^{11} - 1)/2 = 9k + 4$
Hence, the remainder is $4$ when $(3^{11} - 1)/2$ is divided by $9$.
A: $$\frac{3^{11}-1}{2}=\frac{3-1}{2}(3^{10}+3^{9}+3^{8}+3^{7}+3^{6}+3^{5}+3^{4}+3^{3}+3^{2}+3+1)\equiv4$$
