Felicia observed getting “6 spots” 3 times out of 6 rolls of a six-sided die. Eve suggested that the die is biased towards “6 spots”. In order to quantitatively evaluate Eve’s suggestion, Felicia set up the null hypothesis that P(“6 spots”) = 1/6. Which of the following choices has exactly those events that are equally or more extreme than the observed event?
Getting 6 spots A) 0,1,2 times B) 0,1,2,3 times C) 3,4,5,6 times D) 4,5,6 times
Using binomial distribution formula, I calculated that when "6 spots" is obtained 4,5 or 6 times per 6 rolls, then the null hypothesis would be rejected and the die is biased. Am i right that the answer is D?