Exercise says this:
Six cubic dice are thrown (not loaded). Calling a success to get a 5 or a 6,
Calculates the probability of obtaining:
- A) Exactly three successes.
- B) A maximum of three successes.
- C) At least three successes.
My question is this:
It is like repeating the experiment of throwing a dice, but 6 times? That is, a binomial distribution.
Or are we talking about $6 ^ 6$ possibilities and the experiment is repeated only once?
If it were the first case, my $p = 1/3$ and my $n = 6$. Being $X: "$Sometimes I get either the number 5 or the number 6$"$ I have $X$ ~ $Bin (6;1 / 3)$