# Can you calculate the probability of complement conditional

Given $P(A|B) = x$, what can you say about $P(\overline{A}|B)$?

Can we say $1 - x$?

• Possible duplicate of Negation of Bayes' theorem. – johny Feb 13 '17 at 23:24
• The proposed duplicate is a fairly circuitous presentation of ideas at best, starting with an incorrect statement of conditional probability (or of Bayes' Theorem, hard to say). I don't think it makes a compelling duplicate. – hardmath Feb 14 '17 at 1:25