Statistics probability die question Suppose a die has been loaded so that a six is scored five times more often than any other score, while all the other scores are equally likely. Express your answers to three decimals. 
I have gotten the following answers.
What is the probability of scoring a three? 
0.090909091
I have deciphered since it is a 11 sided die so I simply came up with 1/11 since there is only 1/11 chance of getting a 3
What is the probability of scoring a six? 
0.454545455
I have reasoned since there are 5 chances in the 11 sided die so I have gotten 5/11.
I have gotten both of them wrong. What are the answers?
 A: Let $x$ be the probablity of getting a particular nonsix number. So, by question the probablity of getting a six is $5x$. 
Since there are 5 nonsix numbers, the probablity of getting a nonsix number is $5x$. 
Since the probablity of getting a number is $1$, the probablity of getting a six $5x$, and getting a nonsix also $5x$, so:
$$1=5x+5x$$
Solving which we get:
$$x=0.1$$
So, since the probablity of getting a particular nonsix is $x$, the probablity of getting $3$ is $0.1$.
Similarly, the probablity of getting a $6$ is $5x$, so it is $0.5$
A: A die with 5 times the probability of rolling a six is the same as a ten sided die with five sixes on it. As the sides are 1, 2, 3, 4, 5, 6, 6, 6, 6, 6.
Probability of rolling a 3 = $\frac 1{10} = 0.1$
Probability of rolling a 6 = $\frac 5{10} = 0.5$
A: Possibly the problem is in the interpretation of 'five times more often than any other score'. It can be read in two ways.
You read it as: 'the probability of getting 6 is 5 times the probability of getting 3'.
The other way of reading it (which is probably intended) is as: 'the probability of getting 6 is 5 times the probability of getting a non-6'. 
In your 11 sided die the number of sides which are non-sixes is still pretty high even if only one of them reads 3.
