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I cannot find the range of this reciprocal function: 1/(x+1) whose domain is {x:x≥0, x a real number}.

I could draw the graph of this function but my confusion is if x-values are getting bigger from 0, then y-values are getting closer to 0 or approaching infinity, which means y-values are not getting bigger as x-values get bigger. Then how do I write the range?

Thanks in advance.

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1 Answer 1

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The $y$ values cannot approach $\infty$, the maximum value of $y$ is $1$ when $x=0$. As you say the function decreases, approaching $0$ but not getting there, so the range is $(0,1]$

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  • $\begingroup$ Thanks for the solution. Highly appreciate it. $\endgroup$
    – tantrik
    Commented Jan 29, 2017 at 17:34

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