# Show that the sum of finite discrete Markov-chain transition probability is one

A little problem I am asked to do, but that I don't get.

The definition of a Markov chain transition probability is :

$P(x_{t+1}=j|x_t=i) = P_{ij}$, where there are n possible states

I am asked to prove that $\sum_{j=1}^n P_{ij} = 1$ for all i.

I just don't see how to prove this, as it seems like a trivial property that the sum of possible events' probabilities sum to 1. Any help? Thank you.

Say I have a a state space $E$. Then I can say that
$$\sum_{j \in E}P_{ij}=\sum_{j \in E}P(X_{n+1}=j|X_n=i)=$$$$P(\cup_{j \in E}(X_{n+1}=j|X_n=i)=P(X_{n+1}\in E|X_n=i)=1$$