I want to find an example of an infinitly differentiable hölder continuous function with parameter $\alpha=1$, i.e. $f\in C^{0,1}$ for $f:A\to B\subset \mathbb{R}$, where $A$ is closed set in $\mathbb{R}^n$. For simplicity let $A=[a,b]^n$. Now if $n=1$, I would take the simple polynomial $f(x)=x$, which is infinetly differentiable and, since it is lipschitz, it is hölder continuous with parameter $\alpha =1$. My problem is that the functions range should be a subset of $\mathbb{R}$. So I do not see how to generalize this in higher dimension. For example the norm function, would be Lipschitz and it also has the right range, but is however not infinitely differentiable.

Thank you for your help.


  • 1
    $\begingroup$ You want an infinitely differentiable function with range R on a compact set? Well, it would be continuous, and continuous functions on compact sets have bounded range. $\endgroup$
    – abnry
    Oct 11, 2012 at 13:39
  • $\begingroup$ @nayrb Sorry for the confusion! It does not have to be whole $\mathbb{R}$. But the evaluation of the function should be a real number. $\endgroup$
    – user20869
    Oct 11, 2012 at 13:44
  • $\begingroup$ Will you be satisfied with a constant function $f:R^n \rightarrow R$ as an infinitely differentiable lipschitz function? $\endgroup$
    – abnry
    Oct 11, 2012 at 13:53
  • $\begingroup$ @nayrb Actually I would like to have a more interesting example :) $\endgroup$
    – user20869
    Oct 11, 2012 at 13:59

1 Answer 1


Take $f$ a smooth bounded function with bounded derivative, and take $g(x):=f(\lVert x\rVert^2)$, where $\lVert \cdot\rVert$ is the Euclidian norm. Then $$|g(x)-g(y)|=\left|\int_0^1\partial_t g(tx+(1-t)y)dt\right|=\left|\sum_{j=1}^n2(x_i-y_i)f'(\lVert tx+(1-t)y\rVert^2)dt\right|\leq 2n\lVert x-y\rVert \sup_{v\in\Bbb R^n}|f'(v)|.$$ Example: $f(t)=e^{-t^2}$.


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