0
$\begingroup$

This question already has an answer here:

$1^n$+$2^n$+$3^n$+$\dots$+$m^n$. $(m,n\in\mathcal N)$

$m,n\ge2$

$\endgroup$

marked as duplicate by Jorge Fernández Hidalgo, TravisJ, C. Falcon, zhoraster, Behrouz Maleki Jan 20 '17 at 19:27

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • 3
    $\begingroup$ Keyword: Faulhaber's formula. $\endgroup$ – dxiv Jan 20 '17 at 18:16
  • $\begingroup$ ok i got my answer. thanks :) $\endgroup$ – RAJAT303 Jan 20 '17 at 18:33