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$1^n$+$2^n$+$3^n$+$\dots$+$m^n$. $(m,n\in\mathcal N)$

$m,n\ge2$

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    $\begingroup$ Keyword: Faulhaber's formula. $\endgroup$ – dxiv Jan 20 '17 at 18:16
  • $\begingroup$ ok i got my answer. thanks :) $\endgroup$ – RAJAT303 Jan 20 '17 at 18:33