Calculating velocity with no time given I have the question "An egg falls from a nest 3.70m above the ground. 
Calculate its velocity when it hits the ground and the time it takes to fall".
I know that velocity V = acceleration (a) X time (t) 
I also know that the acceleration in this case is gravity so 9.81 ms$^-2$.  
However, there is no time given and so I do not know how to calculate the velocity of the egg once it has hit the ground.
 A: You can determine the time that it takes for the object to hit the ground.
How? Recall that you can determine the distance traveled after $t$ seconds of fall.
This is done by the formula $d(t)=\frac{9.81t^2}{2}$ (the reason is that you want $\int \limits_{0}^t 9.81xdx$ )
So we have to solve $\frac{9.81t^2}{2}=3.70$.
After finding the value of $t$ the speed is just $9.81t$
Note: I skipped the symbols for the measurements purposefully.
A: Notice that the potential energy is given by:
$$\text{E}_\text{pot}=\text{m}\cdot\text{g}\cdot\text{h}\tag1$$
And the kinetic energy:
$$\text{E}_\text{kin}=\frac{\text{m}\cdot\text{v}^2}{2}\tag2$$
So, set those equal (conservation of energy):
$$\text{E}_\text{pot}=\text{E}_\text{kin}=\text{m}\cdot\text{g}\cdot\text{h}=\frac{\text{m}\cdot\text{v}^2}{2}\space\Longleftrightarrow\space\text{v}=\pm\sqrt{2\cdot\text{g}\cdot\text{h}}\tag3$$
So, for $\text{v}$ we will get:
$$\text{v}\approx\sqrt{2\cdot9.81\cdot3.70}=\sqrt{\frac{36297}{500}}\approx8.520211265\tag4$$
And the time it takes:
$$t\approx\frac{\sqrt{\frac{36297}{500}}}{9.81}=\sqrt{\frac{740}{981}}\approx0.868523065\tag5$$
A: Since acceleration and distance are given, you can use $v^2 = 2as$.
A: In this case, you can use one of Newton's Laws of Constant acceleration:
$$v^2=u^2+2as$$
You are trying to find the final velocity $v$. $u=0 \text{ ms}^{-1}$ is the initial velocity, $a=-g \text{ ms}^{-2}$ and $s=3.70 \text{ m}$.
Then, you can find the time taken using $v=u+at$, by using the velocity you found on the first part.
