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I just wish to confirm if my understanding is correct for the following problem: if there are 5 women and 5 men, how many possibilities exist to form a committee of 3 women and 2 men. so i have computed this problem as below

5C3 x 5C2 = 100 possibilities.

is this correct?


marked as duplicate by Austin Mohr, Namaste, Shailesh, Leucippus, JonMark Perry Jan 19 '17 at 3:52

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    $\begingroup$ Yes, that looks good. Note that you have enough privilege to use the chatroom $\endgroup$ – Joffan Jan 18 '17 at 18:57

Yes. $\binom{5}{3} \times \binom{5}{2} = 100$ is correct.


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