Combinatorics for committee forming [duplicate]

I just wish to confirm if my understanding is correct for the following problem: if there are 5 women and 5 men, how many possibilities exist to form a committee of 3 women and 2 men. so i have computed this problem as below

5C3 x 5C2 = 100 possibilities.

is this correct?

marked as duplicate by Austin Mohr, Namaste, Shailesh, Leucippus, JonMark PerryJan 19 '17 at 3:52

Yes. $\binom{5}{3} \times \binom{5}{2} = 100$ is correct.