A convex polygon has its interior angles in arithmetic progression, the least angle being $120°$ and common difference $5°$. Find the number of sides of the polygon.
To solve this I use the fact that the sum of the interior angles of a convex polygon in $(n-2)180°$. We can write the equation
$$120n + \frac{n(n-1)}{2}5 = (n-2)180.$$
Solving this we get the polynomial $n^2-25n+144=0$. This admits two solutions $9 \ \& \ 16$.
The answer given at the back is $n=9$. So my question is why is $16$ not possible?