# Limit points in closed finite sets?

In ch. 2 of Rudin's Principles of Math Analysis, definition 2.18 gives the definition of a closed set: $E$ is closed if every limit point of $E$ is an interior point of $E$. After that, theorem 2.20 and the following corollary clearly state that a finite point set has no limit points. Yet, the immediate example below clearly states that a nonempty finite set is closed. What exactly am I missing because this sounds like a clear contradiction?

• There is no contradiction. Let $E$ be a nonempty finite set. Then $$\{ \mbox{limit points of } E \} = \emptyset \subseteq E^°$$ so $E$ is closed. Jan 15, 2017 at 10:43
• Something is not right about this. Are you sure that your definition of closed set is correct? Jan 15, 2017 at 10:54
• Crostul, is E^° the closure of E? Jan 15, 2017 at 11:01

With the definition the way you write it, the interval $[0,1]$ would not be closed, since $0$ is not interior. What 2.18 says is that $E$ is closed if every limit point belongs to $E$ (no "interior").